2[3x+1]+4[x-1]=3

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Solution for 2[3x+1]+4[x-1]=3 equation: 


Simplifying
2[3x + 1] + 4[x + -1] = 3

Reorder the terms:
2[1 + 3x] + 4[x + -1] = 3
[1 * 2 + 3x * 2] + 4[x + -1] = 3
[2 + 6x] + 4[x + -1] = 3

Reorder the terms:
2 + 6x + 4[-1 + x] = 3
2 + 6x + [-1 * 4 + x * 4] = 3
2 + 6x + [-4 + 4x] = 3

Reorder the terms:
2 + -4 + 6x + 4x = 3

Combine like terms: 2 + -4 = -2
-2 + 6x + 4x = 3

Combine like terms: 6x + 4x = 10x
-2 + 10x = 3

Solving
-2 + 10x = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 10x = 3 + 2

Combine like terms: -2 + 2 = 0
0 + 10x = 3 + 2
10x = 3 + 2

Combine like terms: 3 + 2 = 5
10x = 5

Divide each side by '10'.
x = 0.5

Simplifying
x = 0.5

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